SELECT DISTINCT `id` as `hid`, `haendler`.*, (6368 * SQRT(2*(1-cos(RADIANS(haendler.lat)) * cos(0.82573795839879) * (sin(RADIANS(haendler.lng)) * sin(0.14643486957158) + cos(RADIANS(haendler.lng)) * cos(0.14643486957158)) - sin(RADIANS(haendler.lat)) * sin(0.82573795839879)))) AS `Distance` FROM `haendler` WHERE `id` IN (807796) ORDER BY `Distance` ASC LIMIT 500 Cleaning work in Oberlunkhofen - 0 Service provider

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